GCSE · AQA Combined Science · Physics Paper 2 · P5 Forces

Forces, for the exam.

The whole of P5 — scalars and vectors, resultant forces, work, springs, motion graphs, acceleration, Newton's laws and stopping distances. Built for both tiers.

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Both tiers in one booklet. Everything here is for Foundation and Higher. Anything that's Higher tier only sits in a purple HT box — Foundation students can skip those. Green boxes are required practicals. Do one topic at a time; each is about 10–15 minutes.

Topic 01 · 4.5.1 · Scalars, vectors & forces

Scalars, vectors & forces

By the end of this topic you'll tell a scalar from a vector, sort contact from non-contact forces, and never again confuse mass with weight.

Part 1Scalars and vectors

A scalar quantity has size (magnitude) only. A vector quantity has size and direction. That direction is the whole point — it's why velocity and speed aren't the same thing.

We draw a vector as an arrow: the length shows the size, and the way it points shows the direction. A force is a vector, so it always has both a strength and a direction.

Scalars vs vectors

Scalars
Speed, distance, mass, energy, time, temperature.
Vectors
Velocity, displacement, force, weight, acceleration, momentum.

A force is a push or a pull on an object, caused by it interacting with something else. Forces come in two families. A contact force needs the objects to be touching. A non-contact force acts at a distance, with no touching at all.

TWO FAMILIES OF FORCE CONTACT Friction Air resistance Tension Normal contact NON-CONTACT Gravity (weight) Magnetism Electrostatic
Contact forces need touching; non-contact forces act at a distance

⚠ Watch out — direction matters

Two forces of the same size but pointing opposite ways are not the same. A 10 N push right and a 10 N push left cancel out. Because a force is a vector, you must always say which way it points, and draw the arrow the right length and direction.

Quick check

Which of these is a non-contact force?

  • AFriction between a tyre and the road
  • BThe tension in a tow rope
  • CThe gravitational pull of the Earth on a ball
  • DAir resistance on a falling skydiver
Show answer
C. Gravity acts without anything touching, so it's a non-contact force. Friction, tension and air resistance all need surfaces in contact, so they're contact forces.

Part 2Mass and weight

Mass is the amount of matter in an object, measured in kilograms (kg). It never changes — you have the same mass on the Moon as on Earth. Weight is the force of gravity pulling on that mass, measured in newtons (N). Weight changes if the gravitational field strength changes.

Weight acts straight down from a single point called the centre of mass. Weight is directly proportional to mass: double the mass, double the weight.

Equation

W = m g recall
weight (N) = mass (kg) × gravitational field strength (N/kg). On Earth, g = 9.8 N/kg.

Worked example — weight of a person

A student has a mass of 60 kg. Calculate their weight on Earth. (g = 9.8 N/kg)

EquationW = m g
Sub in= 60 × 9.8
Answer= 588 N

⚠ Watch out — mass ≠ weight

Mass is in kg; weight is a force in N. Don't say a person "weighs 60 kg" — that's their mass. On the Moon (g ≈ 1.6 N/kg) their mass is still 60 kg, but their weight is much smaller. We measure weight with a calibrated spring balance (newtonmeter).

Quick check

A bag has a mass of 4 kg. What is its weight on Earth? (g = 9.8 N/kg)

  • A4 N
  • B0.41 N
  • C39.2 N
  • D9.8 N
Show answer
C — 39.2 N. W = m g = 4 × 9.8 = 39.2 N. Answer A confuses weight (a force in N) with the mass; B divides instead of multiplying.
Topic 1 — quick quiz
Click to reveal · 4 questions
  1. State the difference between a scalar and a vector quantity.
    A scalar has magnitude only; a vector has magnitude and direction.
  2. Give one contact force and one non-contact force.
    Contact: e.g. friction, air resistance, tension or normal contact force. Non-contact: e.g. gravity, magnetism or electrostatic force.
  3. Write the weight equation and state the unit of each quantity.
    W = m g. Weight in newtons (N), mass in kg, gravitational field strength in N/kg.
  4. An astronaut takes a 2 kg tool to the Moon (g = 1.6 N/kg). State its mass and its weight there.
    Mass is unchanged: 2 kg. Weight = m g = 2 × 1.6 = 3.2 N (much less than on Earth).
Topic 02 · 4.5.1.3 · Resultant forces

Resultant forces & free body diagrams

How to add up the forces on an object into a single resultant — and the Higher-tier skill of splitting one force into two.

Part 1Combining forces in a line

Usually several forces act on an object at once. You can always replace them with a single force that has the same effect — the resultant force.

When forces act along the same line, just add them up, treating one direction as positive and the opposite as negative. Forces the same way add; forces opposite ways subtract. A free body diagram shows the object as a dot or box with an arrow for each force acting on it.

FORCES ALONG ONE LINE box 30 N → ← 10 N Resultant = 30 − 10 = 20 N to the right
Forces on the same line: add along it, subtract against it

Worked example — resultant force

A sledge is pulled forwards with 200 N. Friction pushes back with 75 N. Find the resultant force.

Take forwards as +forward 200 N, backward −75 N
Addresultant = 200 − 75
Answer= 125 N forwards

⚠ Watch out — balanced ≠ no forces

If the resultant force is zero, the forces are balanced — but that doesn't mean nothing is pushing. A car at steady speed has thrust balancing drag; the resultant is zero, so it just keeps the same velocity. Always state the direction of a resultant force, not only its size.

Quick check

A box has a 50 N force to the right and a 50 N force to the left. What is the resultant force?

  • A100 N to the right
  • B0 N — the forces are balanced
  • C100 N to the left
  • D50 N in each direction
Show answer
B — 0 N. Equal and opposite forces cancel, so the resultant is zero (balanced). The box keeps moving at constant velocity, or stays still.

Part 2Forces at angles

When forces don't act along the same line, a single arrow can still represent their combined effect. On Higher tier you also need to do the reverse — split one force into two.

Higher tier — resolving a force into components

A single force can be resolved into two forces at right angles that have the same overall effect — usually a horizontal and a vertical component. You do this with a scale vector diagram: draw the force as an arrow to scale, then draw the horizontal and vertical components that complete the rectangle.

The same scale-diagram method finds the resultant of two forces at an angle: draw them tip-to-tail to scale and measure the single arrow from start to finish. A free body diagram in equilibrium has components that cancel in both directions.

Topic 2 — quick quiz
Click to reveal · 4 questions
  1. What is meant by the resultant force on an object?
    The single force that has the same effect as all the forces acting on the object combined.
  2. A car has 600 N of thrust and 600 N of drag. State the resultant force and what the car does.
    Resultant = 600 − 600 = 0 N. The forces are balanced, so the car continues at constant velocity.
  3. A rocket has 5000 N thrust up and 2000 N weight down. Find the resultant force.
    Resultant = 5000 − 2000 = 3000 N upwards.
  4. [HT] What does it mean to "resolve" a force?
    To split a single force into two components at right angles (e.g. horizontal and vertical) that together have the same effect.
Topic 03 · 4.5.2 · Work & energy

Work done & energy

When a force moves something, it does work — and where that energy ends up when friction gets involved.

Part 1Work means transferring energy

Work is done whenever a force moves an object through a distance. Doing work transfers energy — the work done equals the energy transferred. Work is measured in joules (J), the same unit as energy.

The distance must be measured along the line of the force. One joule of work is done when a force of 1 N moves an object 1 m in the direction of the force, so 1 J = 1 N m.

Equation

W = F s recall
work done (J) = force (N) × distance moved along the line of action of the force (m)

Worked example — pushing a crate

A worker pushes a crate with a force of 150 N across 4 m of floor. Calculate the work done.

EquationW = F s
Sub in= 150 × 4
Answer= 600 J
WORK = FORCE × DISTANCE force F distance s
Distance is measured along the direction of the force

⚠ Watch out — no movement, no work

If the object doesn't move, no work is done by that force, however hard you push. Holding a heavy bag still feels tiring, but s = 0, so the work done on the bag is 0 J. The distance must also be along the line of the force, not at an angle to it.

Part 2Work against friction

When you do work against friction, the energy you transfer doesn't disappear — it ends up in the thermal store of the object and its surroundings. That's why rubbing your hands together warms them, and why brakes and tyres get hot.

So work done against friction causes a rise in temperature. The energy is dissipated, spread out and harder to use — but it is still conserved.

Quick check

A force of 20 N drags a box 5 m across rough ground. How much work is done, and where does most of the energy end up?

  • A100 J — into the thermal store (the ground and box warm up)
  • B4 J — into the kinetic store only
  • C25 J — energy is used up by friction
  • D100 J — energy is destroyed by friction
Show answer
A — 100 J. W = F s = 20 × 5 = 100 J. Work done against friction is transferred to the thermal store, warming the surfaces. C and D use the banned ideas "used up" and "destroyed" — energy is conserved.
Topic 3 — quick quiz
Click to reveal · 4 questions
  1. Write the work done equation and state the unit of work.
    W = F s. Work is measured in joules (J), where 1 J = 1 N m.
  2. A 60 N force moves a trolley 3 m in the direction of the force. Calculate the work done.
    W = F s = 60 × 3 = 180 J.
  3. A person holds a 100 N box still for one minute. How much work is done on the box? Explain.
    0 J. The box does not move (s = 0), so no work is done on it.
  4. What happens to the energy transferred when work is done against friction?
    It is transferred to the thermal store of the object and surroundings, causing a temperature rise.
Topic 04 · 4.5.3 · Forces & elasticity

Forces & elasticity

Hooke's law, the difference between elastic and inelastic, and the required practical that draws it all together.

Part 1Stretching springs

To change the shape of a spring you need more than one force — one to stretch each end (or to compress, or to bend). With one force the spring would just move off, not deform.

Up to a point, the extension is directly proportional to the force — that's Hooke's law. Stretch it too far and you pass the limit of proportionality, where the line stops being straight.

Equation

F = k e recall
force (N) = spring constant (N/m) × extension (m). The spring constant k is the stiffness — a bigger k means a stiffer spring.

Deformation is elastic if the object returns to its original shape when the force is removed. It's inelastic if it stays permanently stretched or bent. The work done in stretching a spring (elastically) is stored in its elastic potential store.

FORCE vs EXTENSION extension e force F limit of proportionality straight: F ∝ e
A force–extension graph is a straight line until the limit of proportionality

⚠ Watch out — extension, not length

In F = k e, e is the extension — how much longer the spring has become — not its total length. Measure from the natural (unstretched) length. Extension must be in metres, so a 5 cm stretch is 0.05 m. Beyond the limit of proportionality, F = k e no longer holds.

Worked example — spring constant

A force of 6 N stretches a spring by 0.04 m. Calculate the spring constant.

EquationF = k e → k = F ÷ e
Sub in= 6 ÷ 0.04
Answer= 150 N/m

Part 2Measuring the relationship

Force & extension of a spring

Aim: investigate the relationship between the force applied to a spring and its extension (Hooke's law).

  1. Clamp a spring vertically from a stand and measure its natural length with a ruler (read at eye level).
  2. Hang a known weight (e.g. 1 N) on the spring and record the new length.
  3. Work out the extension = new length − natural length.
  4. Add weights one at a time, recording length each time, until you have several readings.
  5. Plot a graph of force (y-axis) against extension (x-axis) and find the gradient — that's the spring constant k.

Control / improve: add weights in small, equal steps and don't exceed the limit of proportionality (or the line will curve). Read the ruler at eye level to avoid parallax error. A straight line through the origin confirms F ∝ e.

Quick check

A spring has a spring constant of 25 N/m. What force is needed to stretch it by 0.20 m?

  • A125 N
  • B5 N
  • C0.008 N
  • D50 N
Show answer
B — 5 N. F = k e = 25 × 0.20 = 5 N. Answer A divides the wrong way; remember to keep extension in metres.
Topic 4 — quick quiz
Click to reveal · 4 questions
  1. State Hooke's law.
    The extension of a spring is directly proportional to the force applied, up to the limit of proportionality.
  2. What is the difference between elastic and inelastic deformation?
    Elastic: the object returns to its original shape when the force is removed. Inelastic: it stays permanently deformed.
  3. A spring (k = 40 N/m) is stretched by a 12 N force. Calculate the extension.
    e = F ÷ k = 12 ÷ 40 = 0.3 m.
  4. In the required practical, why must you not exceed the limit of proportionality?
    Beyond it, extension is no longer proportional to force, so the graph curves and F = k e stops working.
Topic 05 · 4.5.6.1 · Speed & velocity

Distance, displacement, speed & velocity

The scalar–vector pairs of motion, the typical speeds you're expected to know, and reading a distance–time graph.

Part 1The words, and one equation

Distance is how far you travel — a scalar, no direction. Displacement is the straight-line distance and direction from start to finish — a vector. Walk a full lap of a track and your distance is the lap length, but your displacement is zero.

Speed is a scalar (how fast, no direction). Velocity is speed in a stated direction — a vector. So an object can move at constant speed but changing velocity, if its direction keeps changing (like a car going round a roundabout).

Equation

s = v t recall
distance travelled (m) = speed (m/s) × time (s). Rearrange to v = s ÷ t to find speed.

Typical speeds (you should recall roughly)

Walking ≈ 1.5 m/s
Running ≈ 3 m/s · cycling ≈ 6 m/s.
Car ≈ 25 m/s
Train ≈ 55 m/s · plane ≈ 250 m/s.
Sound in air ≈ 330 m/s
A walking wind speed varies a lot with weather.

Worked example — speed of a runner

A runner covers 200 m in 25 s. Calculate their average speed.

Equationv = s ÷ t
Sub in= 200 ÷ 25
Answer= 8 m/s

⚠ Watch out — speed and velocity aren't the same

An object can move at constant speed but have a changing velocity if its direction changes — think of a car driving steadily round a bend. Changing velocity means it's accelerating, even though the speedometer reading is constant.

Part 2Distance–time graphs

On a distance–time graph, the gradient (slope) is the speed. A steeper line means faster; a horizontal line means stationary; a curve means the speed is changing.

DISTANCE–TIME GRAPH time distance moving stopped faster
Gradient = speed. Flat line = stationary; steeper = faster
Quick check

On a distance–time graph, a horizontal (flat) line means the object is:

  • Amoving at constant speed
  • Bstationary (not moving)
  • Caccelerating
  • Dmoving backwards
Show answer
B — stationary. A flat line has zero gradient, so the distance isn't changing: the object is not moving. A straight sloped line would be constant speed.
Topic 5 — quick quiz
Click to reveal · 4 questions
  1. Explain the difference between distance and displacement.
    Distance is the total path length (a scalar); displacement is the straight-line distance and direction from start to finish (a vector).
  2. A car travels at 25 m/s for 8 s. How far does it go?
    s = v t = 25 × 8 = 200 m.
  3. State a typical speed for a person walking and for sound in air.
    Walking ≈ 1.5 m/s; sound in air ≈ 330 m/s.
  4. How do you find the speed from a distance–time graph?
    Find the gradient (slope) of the line — distance ÷ time.
Topic 06 · 4.5.6.1 · Acceleration

Acceleration

How fast velocity is changing, reading a velocity–time graph, and the given equation that links speed to distance.

Part 1The rate of change of velocity

Acceleration is how quickly velocity changes, measured in metres per second squared (m/s²). Speeding up is a positive acceleration; slowing down is a negative acceleration, also called deceleration.

Equations

a = Δv ÷ t recall
acceleration (m/s²) = change in velocity (m/s) ÷ time taken (s)
v² − u² = 2 a s given
(final velocity)² − (initial velocity)² = 2 × acceleration (m/s²) × distance (m). Use when there's no time given.

Worked example — accelerating car

A car speeds up from 8 m/s to 20 m/s in 6 s. Calculate its acceleration.

Δvchange in velocity = 20 − 8 = 12 m/s
Sub ina = Δv ÷ t = 12 ÷ 6
Answer= 2 m/s²

⚠ Watch out — Δv is the change

Use the change in velocity (final − initial), not the final velocity. For an object slowing down, the acceleration is negative. Objects falling freely near Earth accelerate at about 9.8 m/s² — but with air resistance, an object can reach a constant terminal velocity where the resultant force, and so the acceleration, is zero.

Part 2Velocity–time graphs

On a velocity–time graph, the gradient is the acceleration and the area under the line is the distance travelled. A flat line means constant velocity (zero acceleration); a straight slope means constant acceleration.

VELOCITY–TIME GRAPH time velocity slope = a area = distance constant velocity
Gradient = acceleration · area under the line = distance travelled
Quick check

A motorbike accelerates uniformly from rest at 3 m/s² over a distance of 24 m. Use v² − u² = 2 a s to find its final velocity.

  • A12 m/s
  • B144 m/s
  • C72 m/s
  • D8 m/s
Show answer
A — 12 m/s. u = 0, so v² = 2 a s = 2 × 3 × 24 = 144. v = √144 = 12 m/s. Answer B forgets to take the square root.
Topic 6 — quick quiz
Click to reveal · 4 questions
  1. Define acceleration and state its unit.
    Acceleration is the rate of change of velocity (change in velocity per second). Unit: m/s².
  2. A train slows from 30 m/s to 6 m/s in 8 s. Calculate its acceleration.
    a = Δv ÷ t = (6 − 30) ÷ 8 = −24 ÷ 8 = −3 m/s² (a deceleration).
  3. What two things can you find from a velocity–time graph?
    The acceleration (the gradient) and the distance travelled (the area under the line).
  4. A car at 10 m/s accelerates at 2 m/s² over 75 m. Use v² − u² = 2 a s to find its final speed.
    v² = u² + 2 a s = 10² + 2 × 2 × 75 = 100 + 300 = 400. v = 20 m/s.
Topic 07 · 4.5.6.2 · Newton's laws

Newton's laws of motion

Three laws that tie forces to motion — plus inertia, and the Higher-tier idea of momentum.

Part 1The first and second laws

Newton's first law: if the resultant force on an object is zero, a still object stays still and a moving object keeps the same velocity (same speed and direction). So a car at steady speed has balanced forces. To change velocity, you need an unbalanced force.

The tendency of an object to keep its state of rest or motion is its inertia. Newton's second law tells you how much it accelerates: the acceleration is proportional to the resultant force and inversely proportional to the mass.

Equation

F = m a recall
resultant force (N) = mass (kg) × acceleration (m/s²). The inertial mass measures how hard it is to change an object's velocity.

Worked example — force on a trolley

A 2 kg trolley accelerates at 3 m/s². Calculate the resultant force on it.

EquationF = m a
Sub in= 2 × 3
Answer= 6 N

⚠ Watch out — F is the resultant force

In F = m a, the F is the resultant (net) force, after you've combined all the forces — not just the force you applied. And greater mass means more inertia: for the same force, a heavier object accelerates less.

SAME FORCE, MORE MASS → LESS ACCELERATION 1 kg big acceleration 4 kg small acceleration
Same force: the larger mass (more inertia) accelerates less

Part 2The third law & momentum

Newton's third law: whenever two objects interact, they exert equal and opposite forces on each other. If you push a wall, the wall pushes back on you just as hard. The two forces are the same size, opposite direction, and act on different objects.

Quick check

A resultant force of 12 N acts on a 4 kg box. What is its acceleration?

  • A48 m/s²
  • B3 m/s²
  • C0.33 m/s²
  • D16 m/s²
Show answer
B — 3 m/s². F = m a → a = F ÷ m = 12 ÷ 4 = 3 m/s². Answer A multiplies instead of dividing.

Higher tier — momentum

A moving object has momentum, a vector given by p = m v — momentum (kg m/s) = mass (kg) × velocity (m/s).

In a closed system (no external resultant force), the total momentum before an event equals the total momentum after — this is the conservation of momentum. So in a collision or explosion, the combined momentum stays the same, even though the objects swap or share it.

Topic 7 — quick quiz
Click to reveal · 4 questions
  1. State Newton's first law.
    If the resultant force is zero, an object stays at rest, or keeps moving at the same velocity.
  2. A 1500 kg car has a resultant force of 3000 N. Calculate its acceleration.
    a = F ÷ m = 3000 ÷ 1500 = 2 m/s².
  3. What is inertia?
    The tendency of an object to stay at rest or keep moving at constant velocity — its resistance to a change in motion. Greater mass = greater inertia.
  4. [HT] Write the momentum equation and state the unit of momentum.
    p = m v. Momentum is measured in kg m/s.
Topic 08 · 4.5.6.3 · Stopping distance

Stopping distance & braking

Why a car needs so much room to stop — thinking distance, braking distance, and the factors that make each one worse.

Part 1Thinking + braking

The stopping distance is the total distance a vehicle travels from the moment a hazard appears to the moment it stops. It is made of two parts:

Thinking distance — how far the car travels during the driver's reaction time, before the brakes are even touched. Braking distance — how far it travels once the brakes are applied, while it slows to a stop.

Key relationship

stopping distance = thinking distance + braking distance
Both parts increase with speed, so the total grows rapidly as the car goes faster.
STOPPING DISTANCE = THINKING + BRAKING thinking braking total stopping distance
Stopping distance is thinking distance plus braking distance

⚠ Watch out — braking distance grows fastest

Thinking distance is proportional to speed, but braking distance grows much faster (roughly with speed squared — the kinetic energy depends on v²). So doubling the speed roughly doubles the thinking distance but quadruples the braking distance. That's the key exam point.

Part 2The factors, and braking forces

Thinking distance increases with a longer reaction time — caused by tiredness, alcohol or drugs, and distractions like phones. (Typical reaction times are around 0.2–0.9 s.)

Braking distance increases with higher speed, poor road conditions (wet or icy — less friction), and poor vehicle condition (worn brakes or bald tyres).

When the brakes are applied, friction at the brake pads does work against the wheels. This transfers energy from the car's kinetic store to the thermal store of the brakes, so the brakes get hot. A larger braking force means a greater deceleration — but very large decelerations can cause skidding and brakes to overheat.

Worked example — braking force from deceleration

A 900 kg car decelerates at 6 m/s² when braking. Estimate the braking force. (Use F = m a)

EquationF = m a
Sub in= 900 × 6
Answer= 5400 N
Quick check

Which of these increases the thinking distance (not the braking distance)?

  • AA wet, icy road
  • BWorn brake pads
  • CThe driver being tired or having drunk alcohol
  • DBald tyres
Show answer
C. Tiredness and alcohol lengthen the driver's reaction time, which increases the thinking distance. Wet roads, worn brakes and bald tyres all increase the braking distance instead.
Topic 8 — quick quiz
Click to reveal · 4 questions
  1. What two distances make up the stopping distance?
    Thinking distance (during the reaction time) + braking distance (while the brakes act).
  2. Give two factors that increase the thinking distance.
    Any two of: tiredness, alcohol or drugs, distractions (e.g. a phone) — all increase the reaction time. (Higher speed too.)
  3. Give two factors that increase the braking distance.
    Any two of: higher speed, wet/icy roads (less friction), worn brakes or bald tyres.
  4. What happens to the car's kinetic energy when it brakes?
    It is transferred to the thermal store of the brakes (by friction), so the brakes get hot.
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